Visual Basic (Declaration)  

Public Overloads Shared Function FrequencyTableOL( _ ByVal sc As SeriesCollection, _ ByVal boundaries() As Double _ ) As SeriesCollection 
Visual Basic (Usage)  Copy Code 


C#  

public static SeriesCollection FrequencyTableOL( SeriesCollection sc, double[] boundaries ) 
Parameters
 sc
 A collection of series objects. For example, to evaluate this indicator for two series you will need to pass a series collection containing this two series.
 boundaries
 A strictly increasing sequence of boundaries of the intervals over the real line in which the data sets point will be assigned.
{b_1, b_2, ..., b_n}
,
now the first term of the array returned which represents the frequency table, is the
number of elements from the data set within the interval (infinity, b_1)
,
the second term of the array returned is the number of elements from the data set within
the interval [b_1, b_2)
, and so on...
Example
Consider the set of boundaries { 1, 2, 3, 4, 5 }
, which divide the real
line into six subintervals. Now if we use the open left boundary convention then the
real line will be divided into the subintervals:
(infinity, 1], (1,2], (2,3], (3,4], (4,5], (5, infinity)
Note that, each point on the real line can be assigned to one of these subintervals
and therefore when assigning a data point to one of these intervals there will only
be one subinterval in which it belongs.
Therefore, if we consider the data set { 0.5, 1.4, 1.3, 2.0, 2.3, 4.5, 5.5}
,
if the assign this data set in accordance with the above the conventions then we will
have: using Open Left Boundary (OLB) convention:
 Within the interval
(infinity, 1]
, we assign the data element0.5
; and hence the frequency of this interval is1
.  Within the interval
(1, 2]
, we assign the data element1.4, 1.3, 2.0
; and hence the frequency of this interval (wrt OLB convention) is3
.  Within the interval
(2, 3]
, we assign the data element2.3
, and hence the frequency of this interval (wrt OLB convention) is1
.  Within the interval
(3, 4]
, we assign no data elements, and hence the frequency of this interval (wrt OLB convention) is0
.  Within the interval
(4, 5]
, we assign the data element4.5
, and hence the frequency of this interval (wrt OLB convention) is1
.  Within the interval
(5, infinity)
, we assign the data element5.5
, and hence the frequency of this interval (wrt OLB convention) is1
.
Hence, in this case the series returned corresponding to the frequency table will be
{1, 3, 1, 0, 1, 1}
.