Visual Basic (Declaration)  

Public Overloads Shared Function CFrequencyTableAOL( _ ByVal s As Series, _ ByVal boundaries() As Double _ ) As Series 
Visual Basic (Usage)  Copy Code 


C#  

public static Series CFrequencyTableAOL( Series s, double[] boundaries ) 
Parameters
 s
 A statistical series.
 boundaries
 A strictly increasing sequence of boundaries of the intervals over the real line in which the data sets point will be assigned.
Exception  Description 

ArgumentException  Thrown if data set or boundaries intervals are null. 
Example
Within this example we work through an illustration in which the cumulative frequency table from above using the open left boundary convention is evaluated.
Consider the set of boundaries { 1, 2, 3, 4, 5 }
, which divide the real
line into six subintervals. Now if we use the open left boundary convention then
the real line will be divided into the subintervals:
(infinity, 1], (1,2], (2,3], (3,4], (4,5], (5, infinity)
Note that, each point on the real line can be assigned to one of these subintervals
and therefore when assigning a data point to one of these intervals there will only
be one subinterval in which it belongs.
Therefore, if we consider the data set { 0.5, 1.4, 1.3, 2.0, 2.3, 4.5, 5.5}
,
if the assign this data set in accordance with the above the conventions then we will
have: using Open Left Boundary (OLB) convention:
 Within the interval
(infinity, 1]
, we assign the data element0.5
; and hence the frequency of this interval is1
.  Within the interval
(1, 2]
, we assign the data element1.4, 1.3, 2.0
; and hence the frequency of this interval (wrt OLB convention) is3
.  Within the interval
(2, 3]
, we assign the data element2.3
, and hence the frequency of this interval (wrt OLB convention) is1
.  Within the interval
(3, 4]
, we assign no data elements, and hence the frequency of this interval (wrt OLB convention) is0
.  Within the interval
(4, 5]
, we assign the data element4.5
, and hence the frequency of this interval (wrt OLB convention) is1
.  Within the interval
(5, infinity)
, we assign the data element5.5
, and hence the frequency of this interval (wrt OLB convention) is1
.
Now in follows that the associated values of the cumulative frequency table are given by:
 Cumulative frequency table above
infinity
is:1 + 1 + 0 + 1 + 3 + 1 = 7
 Cumulative frequency table above
1
is:1 + 0 + 1 + 3 + 1 = 6
 Cumulative frequency table above
2
is:0 + 1 + 3 + 1 = 5
 Cumulative frequency table above
3
is:1 + 3 + 1 = 5
 Cumulative frequency table above
4
is:3 + 1 = 4
 Cumulative frequency table above
5
is:1
Hence, for this case the series returned by this methods to represent the cumulative
frequency table would be: {7, 6, 5, 5, 4, 1}
.